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Jixi

If we can do the least squares approximation with just these terms, does that mean there's no need to explicitly calculate the hessian? Or can it be thought of as two different ways to calculate for the change in p?

edit: oh wait, I see, on the next slide in calculating the leastsquares
you find the hessian matrix in the process of doing so

motoole2

Sounds like you got it! We are simply solving a least squares problem here; the Hessian comes out as a term in our closed-form expression for the solution of this problem.